Consider the heterogeneous equilibrium
`CaCO_(3) hArr CaO(s)+CO_(2)(s), K_(p)=4xx10^(2) atm …(i)`
`C(s)+CO_(2)(g) hArr 2CO(g), K'_(p)=2 atm …(ii)`
Calculate the partial pressure of `CO(g)` when `CaCO_(3)` and `C` are mixed and allowed to attain equilibrium at the temperature for which the above two equilibria have been studied.

Answer

A, B, C

Explanation

Equilibrium I
`CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)`
Given `K_(P)=4xx10^(-2)=P'_(CO_(2))`
Equilibrium II
Also `C(s)+CO_(2)(g) hArr 2CO(g)`
`K_(P)=((P_(CO))^(2))/(P'_(CO_(2)))=2.0`
Now both are at equilibrium and thus `P'_(CO_(2))=4xx10^(-2)`
which should remain constant, thus
`2.0=((P'_(CO))^(2))/(4xx10^(-2))`
or `P'_(CO)=sqrt(4xx10^(-2)xx2)=0.28`