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Consider the chemical reaction: unders...

Consider the chemical reaction:
`underset(("Green solution"))(Ni^(2+)(aq))+6NH_(3)(aq) hArr underset(("Blue solution"))([Ni(NH_(3))_(6)]^(2+)) (aq)`
When `H^(o+)(aq)` is added, the colour green is favoured. Use one or more of the following interpretations to answer the questions:
i. Some unreacted `Ni^(2+)(aq)` is present in the solution at equilibrium
ii. Some unreacted `NH_(3)(aq)` is present in the solution at equilibrium
iii. The colour change indicates new equilibrium conditions with reduced `[Ni(NH_(3))_(6)]^(2+)(aq)`
iv. The colour change indicates new equilibrium conditions with increased `[Ni(NH_(3))_(6)]^(2+)(aq)`.
The deepening of blue colour on dissolving more `Ni(NO_(3))_(2)` supports interpretation (s).

A

i only

B

i and iv only

C

ii and iv only

D

i and ii only

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given chemical equilibrium and the effects of adding `H^(o+)(aq)` and `Ni(NO3)2` on the equilibrium state. ### Step-by-Step Solution: 1. **Identify the Reaction and Equilibrium**: The reaction is: \[ \text{Ni}^{2+}(aq) + 6\text{NH}_3(aq) \rightleftharpoons [\text{Ni(NH}_3)_6]^{2+}(aq) \] The green solution corresponds to `Ni^(2+)`, and the blue solution corresponds to the complex ion `[\text{Ni(NH}_3)_6]^{2+}`. 2. **Effect of Adding `H^(o+)(aq)`**: When `H^(o+)(aq)` is added, it favors the formation of `Ni^{2+}` ions, shifting the equilibrium to the left. This results in a green color being favored, indicating that the concentration of the complex ion decreases. 3. **Interpretation of the Color Change**: The deepening of the blue color upon adding more `Ni(NO3)2` suggests that the concentration of `Ni^{2+}` ions is increasing. This addition disturbs the equilibrium, causing the reaction to shift to the right to form more of the blue complex. 4. **Evaluating the Interpretations**: - **Interpretation i**: "Some unreacted `Ni^{2+}` is present in the solution at equilibrium." - This is **true** because adding `Ni(NO3)2` increases the concentration of `Ni^{2+}`, which means some `Ni^{2+}` was unreacted initially. - **Interpretation ii**: "Some unreacted `NH3` is present in the solution at equilibrium." - This is **false** because at equilibrium, all `NH3` would have reacted to form the complex, leaving no unreacted `NH3`. - **Interpretation iii**: "The color change indicates new equilibrium conditions with reduced `[Ni(NH3)6]^{2+}`." - This is **false** because the deepening blue color indicates an increase in the concentration of the complex ion, not a reduction. - **Interpretation iv**: "The color change indicates new equilibrium conditions with increased `[Ni(NH3)6]^{2+}`." - This is **true** because the addition of `Ni(NO3)2` increases the concentration of the complex ion, leading to a deeper blue color. 5. **Conclusion**: The interpretations that hold true are: - i: Some unreacted `Ni^{2+}` is present in the solution at equilibrium. - iv: The color change indicates new equilibrium conditions with increased `[Ni(NH3)6]^{2+}`. ### Summary of Interpretations: - True: i and iv - False: ii and iii

To solve the problem, we need to analyze the given chemical equilibrium and the effects of adding `H^(o+)(aq)` and `Ni(NO3)2` on the equilibrium state. ### Step-by-Step Solution: 1. **Identify the Reaction and Equilibrium**: The reaction is: \[ \text{Ni}^{2+}(aq) + 6\text{NH}_3(aq) \rightleftharpoons [\text{Ni(NH}_3)_6]^{2+}(aq) ...
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Consider the chemical reaction: underset(("Green solution"))(Ni^(2+)(aq))+6NH_(3)(aq) hArr underset(("Blue solution"))([Ni(NH_(3))_(6)]^(2+)) (aq) When H^(o+)(aq) is added, the colour green is favoured. Use one or more of the following interpretations to answer the questions: i. Some unreacted Ni^(2+)(aq) is present in the solution at equilibrium ii. Some unreacted NH_(3)(aq) is present in the solution at equilibrium iii. The colour change indicates new equilibrium conditions with reduced [Ni(NH_(3))_(6)]^(2+)(aq) iv. The colour change indicates new equilibrium conditions with increased [Ni(NH_(3))_(6)]^(2+)(aq) . The deepening of blue colour on addition of more NH_(3)(aq) supports interpretation(s).

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