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If K1 and K2 are the respective equilib...

If `K_1` and `K_2` are the respective equilibrium constants for the two reactions
`XeF_6(g)+2HF(g)hArrXeOF_4(g)+2HF(g)`
`XeO_4(g)+XeFe_6(g)hArrXeOF_4(g)+XeO_3(g)`
The equilibrium constant of the reaction, `XeO_4(g)+2HF(g)hArrXeO_3F_2(g)+H_2O(g)` will be

A

`K_(1)//K_(2)^(2)`

B

`(K_(1)//K_(2))^(1//2)`

C

`K_(1)^(2)//K_(2)^(3)`

D

`K_(2)//K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K=K_(2)/K_(1)`
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