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For a hypothetical reaction of kind. A...

For a hypothetical reaction of kind.
`AB_(2)(g)+1/2 B_(2)(g) hArr AB_(3)(g), DeltaH=-x kJ`
More `AB_(3)` could be produceed at equilibrium by

A

Using a catalyst

B

Removing some of `B_(2)`

C

Increasing the temperature

D

Increasing the pressure

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The correct Answer is:
To determine how more \( AB_3 \) could be produced at equilibrium for the reaction: \[ AB_2(g) + \frac{1}{2} B_2(g) \rightleftharpoons AB_3(g), \quad \Delta H = -x \, \text{kJ} \] we need to analyze the effects of various changes according to Le Chatelier's principle and the characteristics of the reaction. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - The reaction involves the conversion of 1 mole of \( AB_2 \) and 0.5 moles of \( B_2 \) into 1 mole of \( AB_3 \). - This means that there is a decrease in the total number of moles from 1.5 moles of reactants to 1 mole of product. 2. **Effect of Pressure**: - According to Le Chatelier's principle, increasing the pressure will favor the side of the reaction that produces fewer moles of gas. - Since the reactants (1.5 moles) produce fewer moles (1 mole of \( AB_3 \)), increasing the pressure will shift the equilibrium to the right, favoring the formation of \( AB_3 \). 3. **Effect of Temperature**: - The reaction is exothermic (as indicated by \( \Delta H = -x \)). - For exothermic reactions, lowering the temperature favors the formation of products. Therefore, decreasing the temperature will also shift the equilibrium to the right, producing more \( AB_3 \). 4. **Effect of Concentration**: - Increasing the concentration of the reactants \( AB_2 \) or \( B_2 \) will shift the equilibrium to the right, favoring the formation of \( AB_3 \). - This is because adding more reactants will increase the chances of them colliding and reacting to form products. 5. **Effect of a Catalyst**: - A catalyst increases the rate of both the forward and reverse reactions equally and does not affect the position of equilibrium. - While it does not change the amount of \( AB_3 \) produced at equilibrium, it allows the system to reach equilibrium faster. 6. **Effect of Removing Reactants**: - Removing \( B_2 \) would decrease the concentration of reactants, which would shift the equilibrium to the left (favoring the formation of reactants), thus not favoring the production of \( AB_3 \). 7. **Effect of Increasing Temperature**: - Increasing the temperature for an exothermic reaction would shift the equilibrium to the left, favoring the reactants and decreasing the production of \( AB_3 \). ### Conclusion: To produce more \( AB_3 \) at equilibrium, one could: - Increase the pressure. - Decrease the temperature. - Increase the concentration of \( AB_2 \) or \( B_2 \).

To determine how more \( AB_3 \) could be produced at equilibrium for the reaction: \[ AB_2(g) + \frac{1}{2} B_2(g) \rightleftharpoons AB_3(g), \quad \Delta H = -x \, \text{kJ} \] we need to analyze the effects of various changes according to Le Chatelier's principle and the characteristics of the reaction. ...
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