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The system PCl(5)(g) hArr PCl(3)(g)+Cl(2...

The system `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)` attains equilibrium. If the equilibrium concentration of `PCl_(3)(g)` is doubled, the concentration of `Cl_(2)(g)` would become

A

`1//4` its original value

B

`1//2` its original value

C

Twice its original value

D

Unpredictable

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The correct Answer is:
To solve the problem, we need to analyze the equilibrium reaction: \[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \] 1. **Understanding the Initial Condition**: - Let the initial equilibrium concentrations be: - \([PCl_5] = a\) - \([PCl_3] = b\) - \([Cl_2] = c\) 2. **Effect of Doubling \([PCl_3]\)**: - According to the problem, the concentration of \([PCl_3]\) is doubled. Thus, the new concentration of \([PCl_3]\) becomes \(2b\). 3. **Le Chatelier's Principle**: - Le Chatelier's Principle states that if a system at equilibrium is disturbed, the system will shift in a direction that counteracts the disturbance. - In this case, increasing the concentration of \([PCl_3]\) will disturb the equilibrium, causing the reaction to shift to the left (towards the formation of \([PCl_5]\)) to reduce the concentration of \([PCl_3]\). 4. **Change in Concentrations**: - Let \(x\) be the amount of \([PCl_3]\) and \([Cl_2]\) that reacts to restore equilibrium. - The new concentrations will be: - \([PCl_3] = 2b - x\) - \([Cl_2] = c - x\) - \([PCl_5] = a + x\) 5. **Establishing New Equilibrium**: - At the new equilibrium, the concentrations of \([PCl_3]\) and \([Cl_2]\) will adjust such that the equilibrium constant \(K\) remains the same. The equilibrium constant expression is: \[ K = \frac{[PCl_3][Cl_2]}{[PCl_5]} \] - Since we do not have specific values for \(a\), \(b\), and \(c\), we cannot determine the exact values of \(x\), \([Cl_2]\), or \([PCl_5]\) after the shift. 6. **Conclusion**: - The concentration of \([Cl_2]\) will decrease, but the exact new concentration cannot be determined without additional information. Therefore, the answer is that the concentration of \([Cl_2]\) becomes unpredictable.

To solve the problem, we need to analyze the equilibrium reaction: \[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \] 1. **Understanding the Initial Condition**: - Let the initial equilibrium concentrations be: - \([PCl_5] = a\) - \([PCl_3] = b\) ...
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