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The active mass of 64 g of HI in a 2-L f...

The active mass of `64 g` of `HI` in a `2-L` flask would be

A

`2`

B

`1`

C

`5`

D

`0.25`

Text Solution

Verified by Experts

The correct Answer is:
D
Active mass = Concentration `= "mol" L^(-1)`
`[HI]=64/(128xx2)=0.25 M`
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CENGAGE CHEMISTRY ENGLISH-CHEMICAL EQUILIBRIUM-Exercises (Single Correct)
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