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When 4 mol of A is mixed with 4 mol of B...

When `4 mol` of `A` is mixed with `4 mol` of `B, 2 mol` of `C` and `D` are formed at equilibrium, according to the reaction
`A+B hArr C+D`
the equilibrium constant is

A

`4`

B

`1`

C

`1//2`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(,A,+,B,hArr,C,+,D),("Initial",4,,4,,0,,0),("Final",4-x,,4-x,,x,,x),(,x=2,,,,,,):}`
`:. [A]=4-2=2, [B]=4-2=2`
`[C]=2, [D]=2`
`K=([C][D])/([A][B])=(2xx2)/(2xx2)=1`
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