For the reaction `X hArr 2Y` and `Z hArr P+Q` occuring at two different pressure `P_(1)` and `P_(2)`, respectively. The ratio of the two pressure is `3:1`. What will be the ratio of equilibrium constant `Kp2: Kp1`, if degree of dissociation of X and Z are equal.

Options

A. (a) `1:36`
B. (b) `1:12`
C. (c) `1:9`
D. (d) `2:3`

Explanation

To solve the problem, we need to find the ratio of the equilibrium constants \( K_{p2} : K_{p1} \) for the two reactions given the degree of dissociation is equal for both reactions and the ratio of pressures \( P_1 : P_2 = 3 : 1 \).

### Step-by-Step Solution:

1. **Define the Reactions**:
- Reaction 1: \( X \rightleftharpoons 2Y \)
- Reaction 2: \( Z \rightleftharpoons P + Q \)

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