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In atmosphere, SO(2) and NO are oxidised...

In atmosphere, `SO_(2)` and `NO` are oxidised to `SO_(3)` and `NO_(2)`, respectively,w hcih react with water to given `H_(2)SO_(4)` and `HNO_(3)`. The resultant solution is called acid rain. `SO_(2)`dissolves in water to form diprotic acid.
`SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2)`.
`HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7)`
and for equilibrium,
`SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq)`
`K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K`.
Which of the following statement is correct?

A

`H_(2)SO_(3)` is less acidic than `H_(2)SO_(4)`.

B

`HNO_(3)` is less acidic than `HNO_(2)`.

C

`SO_(2)(g)` is reduced in the atmosphere during thunderstron.

D

`CO_(2)` gas develop more acidity in rain water than `SO_(2)`.

Text Solution

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The correct Answer is:
To solve the question regarding the acidity of different acids and the behavior of sulfur dioxide (SO₂) in the atmosphere, we need to analyze the statements provided and determine which ones are correct based on the information given in the problem. ### Step-by-Step Solution: 1. **Understanding the Acids Involved:** - The question mentions sulfurous acid (H₂SO₃) and sulfuric acid (H₂SO₄). We know that sulfuric acid has a higher oxidation state of sulfur compared to sulfurous acid, which generally makes it a stronger acid due to the presence of more oxygen atoms. 2. **Analyzing Statement 1:** - **Statement:** H₂SO₃ is less acidic than H₂SO₄. - **Analysis:** This statement is correct because H₂SO₄ has more oxygen atoms, which increases its ability to donate protons (H⁺ ions) compared to H₂SO₃. Therefore, H₂SO₃ is indeed less acidic than H₂SO₄. 3. **Analyzing Statement 2:** - **Statement:** HNO₃ is less acidic than HNO₂. - **Analysis:** This statement is incorrect. HNO₃ (nitric acid) is a stronger acid than HNO₂ (nitrous acid) because it has a higher oxidation state of nitrogen and more oxygen atoms, which stabilize the negative charge after deprotonation. 4. **Analyzing Statement 3:** - **Statement:** SO₂ gas is reduced in the atmosphere during thunderstorms. - **Analysis:** This statement is incorrect. The problem states that SO₂ is oxidized to SO₃ in the atmosphere, particularly during thunderstorms. Therefore, SO₂ is not being reduced. 5. **Analyzing Statement 4:** - **Statement:** CO₂ gas develops more acidity in rainwater than SO₂. - **Analysis:** This statement is correct. While both CO₂ and SO₂ can contribute to acidity in rainwater, SO₂ leads to the formation of sulfurous acid (H₂SO₃), which is less acidic than the carbonic acid (H₂CO₃) formed from CO₂. However, the overall contribution of SO₂ to acid rain is significant due to its conversion to stronger acids like H₂SO₄. 6. **Conclusion:** - The correct statements are: - Statement 1: H₂SO₃ is less acidic than H₂SO₄ (Correct). - Statement 4: CO₂ gas develops more acidity in rainwater than SO₂ (Correct). - Therefore, the correct options are A and D.
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In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . Which of the following reagnets will given white precipitate with the aqueous solution of sulphurous acid?

In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . The pH of 0.01M aqueous solutioon of sodium sulphite (Na_(2)SO_(3))

In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . The dominant equilibrium in an aqueous solution of sodium hydrogen sulphite (NaHSO_(3)) is 2HSO_(3)^(Theta) (aq) hArr SO_(2) (aq) +SO_(3)^(2-) (aq) + H_(2)O(l) The equilibrium constant for the above reaction is

2H_(2)O hArr H_(3)O^(o+) + overset(Theta)OH,K_(w) = 10^(-14) at 25^(@)C , hence K_(a) is

underline(S)O_(2)+H_(2)O to H_(2)SO_(3)

underline(S)O_(2)+H_(2)O to H_(2)SO_(3)

CaSO_(3)darr+SO_(2)+H_(2)O to Ca(HSO_(3))_(2)

BaSO_(3)darr+SO_(2)+H_(2)O to Ba(HSO_(3))_(2)

BaSO_(3)darr+SO_(2)+H_(2)O to Ba(HSO_(3))_(2)

Cr_(2)O_(7)^(2-)+H^(+)+SO_(3)^(2-) to Cr^(3+)(aq.)+SO_(4)^(2-)

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