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The pH of a solution of weak base at neu...

The `pH` of a solution of weak base at neutralisation with strong acid is `8. K_(b)` for the base is

A

`1.0 xx 10^(-4)`

B

`1.0 xx 10^(-6)`

C

`1.0 xx 10^(-8)`

D

None of these

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The correct Answer is:
To solve the problem, we need to determine the \( K_b \) (base dissociation constant) for a weak base when the pH of its solution at neutralization with a strong acid is given as 8. Here’s how we can approach this step by step: ### Step 1: Understand the Reaction When a weak base (let's denote it as \( B \)) reacts with a strong acid (denote it as \( HA \)), it forms a salt (\( AB \)) and water. The reaction can be represented as: \[ B + HA \rightarrow AB + H_2O \] ### Step 2: Identify the pH and Calculate pOH Given that the pH of the solution at neutralization is 8, we can calculate the pOH using the relationship: \[ \text{pH} + \text{pOH} = 14 \] Thus, \[ \text{pOH} = 14 - \text{pH} = 14 - 8 = 6 \] ### Step 3: Calculate the Concentration of Hydroxide Ions The pOH can be used to find the concentration of hydroxide ions (\( [OH^-] \)): \[ [OH^-] = 10^{-\text{pOH}} = 10^{-6} \, \text{M} \] ### Step 4: Relate Hydroxide Ion Concentration to \( K_b \) At the equivalence point, the salt \( AB \) undergoes hydrolysis to produce hydroxide ions: \[ AB + H_2O \rightleftharpoons A^- + OH^- \] The equilibrium expression for this hydrolysis can be written as: \[ K_b = \frac{[OH^-]^2}{[AB]} \] Assuming that the concentration of the salt \( AB \) is \( C \) (which we will determine later), we can substitute \( [OH^-] \) into the equation: \[ K_b = \frac{(10^{-6})^2}{C} = \frac{10^{-12}}{C} \] ### Step 5: Determine the Concentration \( C \) We know that at neutralization, the pH is 8, which corresponds to the salt being in a solution that is slightly basic due to hydrolysis. However, we do not have the concentration \( C \) provided in the problem. ### Step 6: Conclusion Since we cannot determine \( K_b \) without knowing the concentration \( C \), we conclude that the value of \( K_b \) cannot be calculated with the information provided. ### Final Answer The answer is that we cannot determine \( K_b \) without additional information about the concentration of the salt formed. ---

To solve the problem, we need to determine the \( K_b \) (base dissociation constant) for a weak base when the pH of its solution at neutralization with a strong acid is given as 8. Here’s how we can approach this step by step: ### Step 1: Understand the Reaction When a weak base (let's denote it as \( B \)) reacts with a strong acid (denote it as \( HA \)), it forms a salt (\( AB \)) and water. The reaction can be represented as: \[ B + HA \rightarrow AB + H_2O \] ### Step 2: Identify the pH and Calculate pOH Given that the pH of the solution at neutralization is 8, we can calculate the pOH using the relationship: ...
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