A salt `X` is dissolved in water having `pH =7`. The resulting solution has a `pH` more than `7`. The salt is made by neutralisation of

Options

A. A strong acid and strong base
B. A strong acid and strong weak base
C. A weak acid and weak base
D. A weak acid and strong base

Explanation

To solve the question, we need to analyze the information provided about the salt `X` and its behavior in water.

### Step-by-Step Solution:

1. **Understanding the pH of the Solution**:
- The question states that the salt `X` is dissolved in water with a pH of 7, which is neutral. After dissolving, the resulting solution has a pH greater than 7. This indicates that the solution is basic.

2. **Identifying Hydrolysis**:
- When a salt dissolves in water, it can undergo hydrolysis. Hydrolysis is the reaction of the salt with water, which can affect the pH of the solution.
- A salt formed from a strong acid and a strong base does not undergo hydrolysis and will remain neutral (pH = 7).

3. **Determining the Type of Salt**:
- Since the resulting solution has a pH greater than 7, we can conclude that the salt must be a basic salt. Basic salts are formed from the neutralization of a strong base with a weak acid.

4. **Identifying the Components**:
- A basic salt is formed when a strong base (like NaOH or KOH) reacts with a weak acid (like acetic acid or carbonic acid).
- Therefore, we can deduce that salt `X` is formed from a strong base and a weak acid.

5. **Conclusion**:
- The salt `X` is made by the neutralization of a strong base with a weak acid.

### Final Answer:
The salt `X` is made by the neutralization of a **strong base** (e.g., NaOH) and a **weak acid** (e.g., acetic acid).