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When 0.002mol of acid is added to 250 mL...

When `0.002mol` of acid is added to `250 mL` of a buffer solution, `pH` decreases by `0.02`units. The buffer capacity of the system is

A

(a) `0.1`

B

(b) `0.2`

C

(c) `0.3`

D

(d) `0.4`

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The correct Answer is:
To find the buffer capacity of the system, we can follow these steps: ### Step 1: Understand the definition of buffer capacity Buffer capacity is defined as the number of moles of acid or base added to 1 liter of buffer solution divided by the change in pH that is observed. ### Step 2: Identify the given values - Moles of acid added = 0.002 mol - Volume of buffer solution = 250 mL - Change in pH = 0.02 units ### Step 3: Convert the volume of the buffer solution to liters Since buffer capacity is expressed per liter, we need to convert the volume of the buffer solution from milliliters to liters: \[ 250 \, \text{mL} = 0.250 \, \text{L} \] ### Step 4: Calculate the number of moles of acid added per liter To find the number of moles of acid added per liter, we can use the formula: \[ \text{Moles of acid per liter} = \frac{\text{Moles of acid added}}{\text{Volume of buffer in liters}} \] Substituting the values: \[ \text{Moles of acid per liter} = \frac{0.002 \, \text{mol}}{0.250 \, \text{L}} = 0.008 \, \text{mol/L} \] ### Step 5: Calculate the buffer capacity Now that we have the moles of acid added per liter, we can use the formula for buffer capacity: \[ \text{Buffer Capacity} = \frac{\text{Moles of acid per liter}}{\text{Change in pH}} \] Substituting the values: \[ \text{Buffer Capacity} = \frac{0.008 \, \text{mol/L}}{0.02} \] Calculating this gives: \[ \text{Buffer Capacity} = 0.4 \, \text{mol/L} \] ### Final Answer The buffer capacity of the solution is **0.4 mol/L**. ---

To find the buffer capacity of the system, we can follow these steps: ### Step 1: Understand the definition of buffer capacity Buffer capacity is defined as the number of moles of acid or base added to 1 liter of buffer solution divided by the change in pH that is observed. ### Step 2: Identify the given values - Moles of acid added = 0.002 mol - Volume of buffer solution = 250 mL ...
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