When equal volumes of the following solutions are mixed, the precipitation of AgCl `(K_(sp)=1.8xx10^(-10))` will occur with :

Options

A. `10^(-4)M (Ag^(o+))` and `10^(-4)M (CI^(Theta))`
B. `10^(-5)M (Ag^(o+))` and `10^(-5)M (CI^(Theta))`
C. `10^(-5)M(Ag^(o+))` and `10^(-6)M(CI^(Theta))`
D. `10^(-4)M (Ag^(o+))` and `10^(-10)M (CI^(Theta))`

Answer

A

Explanation

Since equal volumes are added
a. Ionic product `=(10^(-4))/(2) xx (10^(-4))/(2) = (10^(-8))/(4)`
b. Ionic product `= (10^(-5))/(2) xx (10^(-5))/(2) = (10^(-10))/(4)`
c. Ionic produt `= (10^(-5))/(2) xx (10^(-6))/(2) = (10^(-11))/(4)`
d. Ionic product `= (10^(-10))/(2) xx (10^(-10))/(2) = (10^(-20))/(4)`
Only in (a) Ionic product `((10^(-8))/(4)) gt K_(sp) (1.8 xx 10^(-10))` So precipitate will take place only with (a)