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pH of some solution is given by pH = (pK...

`pH` of some solution is given by `pH = (pK_(a_(1))+pK_(a_(2)))/(2)`. This formula is valid for the compound `NaH_(2)BO_(3)`.

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To determine whether the statement about the pH of the solution given by the formula \( pH = \frac{(pK_{a1} + pK_{a2})}{2} \) is valid for the compound \( NaH_2BO_3 \), we can follow these steps: ### Step 1: Understand the Compound - **Identify the nature of \( NaH_2BO_3 \)**: This compound is sodium borate, which is derived from boric acid \( H_3BO_3 \). ### Step 2: Dissociation in Water - **Dissociation Reaction**: When \( NaH_2BO_3 \) is dissolved in water, it dissociates into \( Na^+ \) ions and \( H_2BO_3^- \) ions. The reaction can be represented as: \[ ...
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