Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g `mol^(–1)`.

Explanation

`0.375 M` aqueous solution means that `1000 mL` of the solution contains sodium acetate `=0.375 mol`
`:. 500 mL` of the solution should contain sodium acetage
`=0.375/2 mol`
Molar mass of sodium acetate `=82.0245 g mol^(-1)`
`:.` Mass of sodium acetate required
`=0.375/2 molxx82.0245 g mol^(-1)=15.380 g`