Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g `mL^(–1)` and the mass per cent of nitric acid in it being 69%.

Explanation

Mass percent of `69%` means that `100 g` of nitric acid solution contains `69 g` of nitric acid by mass.
Molar mass of nitric acid `(HNO_(3))=1+14+48`
`=63 g mol^(-1)`
`M=(% "by mass"xx10xxd)/(Mw_(2))=(69xx10xx1.41)/63=15.44 M`