Which one of the following will have the largest number of atoms?
(i) 1 g Au (s)
(ii) 1 g Na (s)
(iii) 1 g Li (s)
(iv) 1 g of Cl2(g)

Explanation

a. `1 g Au=1/197 mol=1/197xx6.02xx10^(23)` atoms
b. `1 g Na=1/23 mol=1/23xx6.02xx10^(23)` atoms
c. `1g Li=1/7 mol =1/7xx6.02xx10^(23)` atoms
d. `1 g Cl_(2)=1/71 mol =1/71xx6.02xx10^(23)` molecules
`=2/71xx6.02xx10^(23)` atoms
Thus, `1 g` of `Li` has the largest number of atoms.