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DeltaU^@ of combustion of methane is -X ...

`DeltaU^@` of combustion of methane is `-X kJ mol^(-1)`. The value of `DeltaH^@` is

A

`=DeltaU^(Θ)`

B

`gt DeltaU^(Θ)`

C

`lt DeltaU^(Θ)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
c
The balance equation for combustion of methane with be
`CH_(4)(g)+2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l)`
Thus, `Deltan_(g)=(n_(p)-n_(r))_(g)=1-3=-2`
`DeltaH^(Θ)=DeltaU^(Θ)+Deltan_(g)RT=-X-2 RT`
Thus, `DeltaH^(Θ) lt DeltaU^(Θ)`
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