For the reaction
`2A(g)+B(g)rarr2D(g)`
`DeltaU^(theta)=-10.55 KJ and Delta S^(theta)=-44.1 JK^(-1)`
Calculate `DeltaG^(Ө)` for the reaction, and predict whether the reaction may occur spontaneously

Explanation

For the given reaction, `Deltan_(g)=2-(3)=-1`
`:. DeltaH^(Θ)=DeltaU^(Θ)+Deltan_(g)RT`
`=-10.5 kJ+(-1)(8.314xx10^(-3)kJ)(298)`
`=-10.5-2.48=-12.98 kJ`
`DeltaG^(Θ)=DeltaH^(Θ)-T DeltaS^(Θ)=-12.98 kJ-298 (-44.1xx10^(-3)k J)`
`=-12.98 kJ+13.14 kJ=0.16 kJ`
As `DeltaG^(Θ)` comes out to be +ve, the reaction will not occur spontaneously.