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The number of unit cells in the Ca atom ...

The number of unit cells in the `Ca` atom lies on the surface of a cubic crystal that is `1.0 cm` in length is

A

`1.11 xx 10^(-8)`

B

`2.22 xx 10^(-8)`

C

`1.11 xx 10^(-7)`

D

`2.22 xx 10^(-7)`

Text Solution

Verified by Experts

The correct Answer is:
A
For bcc , `Z_(eff) = 2`
`:.` Number of atoms `= 2 xx 9.17 xx 10^(22)`
Surface area of one face of a crystal `= (10^(-2)m)^(2)`
`=10^(-4)m^(2)`
Surface area of one face of a unit cell `= a^(2)`
Number of square faces visiable at one face of crustal
`= (10^(-4)m^(2))/((22.17 xx 10^(-12))^(2)m^(2)) = 2.03 xx 10^(15)`

Number of atom per face of unit cell `= 1`
Number of atoms `= 1 xx 2.03 xx 10^(15)`
Fraction of Ca atoms `= (2.03 xx 10^(15))/(2 xx 9.17 xx 10^(22))`
`= 1.11 xx 10^(-8)`
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