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AX,AY,BX, and BY have rock salt type str...

`AX,AY,BX`, and `BY` have rock salt type structure with following internuclear distances:
`|{:("Salt","Anion-anion","Cation-anion"),(,"distance in"Å,"distance in"Å),(AX,2.40,1.70),(AY,1.63,1.15),(BX,2.66,1.88),(By,2.09,1.48):}|`
Ionic radii of `X^(o+)` and `Y^(Θ)`, respectively, are

A

`0.35` and `0.68 Å`

B

`0.68` and `0.35 Å`

C

`1.20` and `0.80 Å`

D

`0.80` and `1.20 Å`

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To find the ionic radii of \(X^{2-}\) and \(Y^{2-}\) for the compounds \(AX\) and \(AY\) with rock salt type structure, we can follow these steps: ### Step 1: Determine the Edge Lengths For the rock salt structure, the anion-anion distance is related to the edge length \(a\) of the cubic unit cell. The relationship is given by: \[ \text{Anion-Anion Distance} = \frac{a}{\sqrt{2}} \] For \(AX\), the anion-anion distance is 2.40 Å: \[ 2.40 = \frac{a_1}{\sqrt{2}} \implies a_1 = 2.40 \times \sqrt{2} = 2.40 \times 1.414 \approx 3.4 \, \text{Å} \] For \(AY\), the anion-anion distance is 1.63 Å: \[ 1.63 = \frac{a_2}{\sqrt{2}} \implies a_2 = 1.63 \times \sqrt{2} = 1.63 \times 1.414 \approx 2.30 \, \text{Å} \] ### Step 2: Calculate Cation-Anion Distances The cation-anion distance is given by: \[ \text{Cation-Anion Distance} = \frac{a}{2} \] For \(AX\), the cation-anion distance is 1.70 Å: \[ 1.70 = \frac{a_1}{2} \implies a_1 = 1.70 \times 2 = 3.4 \, \text{Å} \quad \text{(consistent with previous calculation)} \] For \(AY\), the cation-anion distance is 1.15 Å: \[ 1.15 = \frac{a_2}{2} \implies a_2 = 1.15 \times 2 = 2.30 \, \text{Å} \quad \text{(consistent with previous calculation)} \] ### Step 3: Establish the Relationship Between Ionic Radii In a rock salt structure, the ratio of the cation radius \(R^+\) to the anion radius \(R^-\) is given by: \[ \frac{R^+}{R^-} = 0.414 \] Thus, we can express the cation radius in terms of the anion radius: \[ R^+ = 0.414 R^- \] ### Step 4: Set Up the Equation for AX For \(AX\): \[ R^+ + R^- = 1.70 \, \text{Å} \] Substituting \(R^+\): \[ 0.414 R^- + R^- = 1.70 \] \[ (0.414 + 1) R^- = 1.70 \] \[ 1.414 R^- = 1.70 \implies R^- = \frac{1.70}{1.414} \approx 1.20 \, \text{Å} \] Thus, the ionic radius of \(X^{2-}\) is approximately \(1.20 \, \text{Å}\). ### Step 5: Set Up the Equation for AY For \(AY\): \[ R^+ + R^- = 1.15 \, \text{Å} \] Substituting \(R^+\): \[ 0.414 R^- + R^- = 1.15 \] \[ (0.414 + 1) R^- = 1.15 \] \[ 1.414 R^- = 1.15 \implies R^- = \frac{1.15}{1.414} \approx 0.81 \, \text{Å} \] Thus, the ionic radius of \(Y^{2-}\) is approximately \(0.8 \, \text{Å}\). ### Final Results - Ionic radius of \(X^{2-}\) is approximately \(1.20 \, \text{Å}\). - Ionic radius of \(Y^{2-}\) is approximately \(0.8 \, \text{Å}\).

To find the ionic radii of \(X^{2-}\) and \(Y^{2-}\) for the compounds \(AX\) and \(AY\) with rock salt type structure, we can follow these steps: ### Step 1: Determine the Edge Lengths For the rock salt structure, the anion-anion distance is related to the edge length \(a\) of the cubic unit cell. The relationship is given by: \[ \text{Anion-Anion Distance} = \frac{a}{\sqrt{2}} \] For \(AX\), the anion-anion distance is 2.40 Å: ...
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