Select the correct statement(s).

Options

A. Solids with `F`-centres are paramagnetic.
B. Ferrimagnetic character of `Fe_(3)O_(4)` at room temperature changes to paramagnetic character at `850 K`.
C. Anti-ferrimagetic `V_(2)O_(3)` changes to paramagnetic at `150 K`.
D. Non-stoichiometric `Cu_(2)O` is a `p`-type semiconductor.

Answer

To solve the question, we need to evaluate each of the provided statements regarding solid-state chemistry and determine their correctness.

### Step-by-Step Solution:

1. **Evaluate the First Statement:**
- **Statement:** "Solid with F center are called paramagnetic."
- **Explanation:** F-centers are created when an anion vacancy in a crystal lattice is occupied by an unpaired electron. Since these unpaired electrons contribute to the magnetic properties of the material, solids with F-centers are indeed paramagnetic.
- **Conclusion:** This statement is **correct**.

2. **Evaluate the Second Statement:**
- **Statement:** "Ferromagnetic character of Fe3O4 at room temperature changes to paramagnetic character at 850 Kelvin."
- **Explanation:** At room temperature, Fe3O4 exhibits ferromagnetism due to the alignment of magnetic moments. However, as the temperature increases to 850 K, thermal agitation disrupts this alignment, leading to a transition to paramagnetism.
- **Conclusion:** This statement is **correct**.

3. **Evaluate the Third Statement:**
- **Statement:** "Antiferromagnetic V2O3 changes to paramagnetic at 150 Kelvin."
- **Explanation:** V2O3 is known to exhibit antiferromagnetic properties at lower temperatures. As the temperature rises to 150 K, the thermal energy becomes sufficient to randomize the spins, leading to a paramagnetic state.
- **Conclusion:** This statement is **correct**.

4. **Evaluate the Fourth Statement:**
- **Statement:** "Non-stoichiometric Cu2O is a p-type semiconductor."
- **Explanation:** In non-stoichiometric Cu2O, the copper-to-oxygen ratio is slightly less than 2:1, which results in the absence of some Cu(I) ions. This creates holes in the lattice, which are responsible for the p-type conductivity.
- **Conclusion:** This statement is **correct**.

### Final Conclusion:
All four statements are correct. Therefore, the correct answer is that **all options (A, B, C, and D) are correct**.

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