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Which of the following statements is//ar...

Which of the following statements is//are correct about `TVs` in an fcc unit cell?
Given: Edge length `= a`
Body diagonai `= b`

A

Each `TV` lies at a diastance b//4 from the nearest corner.

B

Each `TV` lies at a distance `3b//4` from the farthest corner.

C

Each `TV` lies at a distance of `sqrt3a//4` from the nearest corner.

D

The distance between two `TV_(s)` is `b//2`.

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The correct Answer is:
To solve the question regarding the tetrahedral voids in a face-centered cubic (FCC) unit cell, we will analyze the given statements one by one based on the properties of FCC lattices. ### Step-by-Step Solution: 1. **Understanding FCC Unit Cell**: - In an FCC unit cell, atoms are located at each of the corners and the centers of each face of the cube. - The edge length of the cube is given as `a`, and the body diagonal is given as `b`. 2. **Finding the Body Diagonal**: - The body diagonal `b` of a cube can be calculated using the formula: \[ b = \sqrt{a^2 + a^2 + a^2} = a\sqrt{3} \] - Therefore, \( b = a\sqrt{3} \). 3. **Position of Tetrahedral Voids**: - In an FCC unit cell, there are 8 tetrahedral voids. The positions of these voids can be determined based on the arrangement of the atoms. - The tetrahedral voids are located at specific fractional coordinates within the unit cell. 4. **Analyzing Each Statement**: - **Option 1**: Each tetrahedral void lies at a distance of \( \frac{b}{4} \) from the nearest corner. - The distance from the corner to the tetrahedral void is indeed \( \frac{b}{4} \). This statement is **correct**. - **Option 2**: Each tetrahedral void lies at a distance of \( \frac{3b}{4} \) from the farthest corner. - The distance from the farthest corner can be calculated as \( b - \frac{b}{4} = \frac{3b}{4} \). This statement is **correct**. - **Option 3**: Each tetrahedral void lies at a distance of \( \frac{\sqrt{3}a}{4} \) from the nearest corner. - Since \( b = a\sqrt{3} \), we have \( \frac{b}{4} = \frac{a\sqrt{3}}{4} \), which is equivalent to \( \frac{\sqrt{3}a}{4} \). This statement is **correct**. - **Option 4**: The distance between two tetrahedral voids is \( \frac{b}{2} \). - The distance between two tetrahedral voids can be calculated based on their positions. It is found to be \( \frac{b}{2} \). This statement is **correct**. 5. **Conclusion**: - All the statements regarding the tetrahedral voids in an FCC unit cell are correct. ### Final Answer: All options are correct regarding the tetrahedral voids in an FCC unit cell. ---

To solve the question regarding the tetrahedral voids in a face-centered cubic (FCC) unit cell, we will analyze the given statements one by one based on the properties of FCC lattices. ### Step-by-Step Solution: 1. **Understanding FCC Unit Cell**: - In an FCC unit cell, atoms are located at each of the corners and the centers of each face of the cube. - The edge length of the cube is given as `a`, and the body diagonal is given as `b`. ...
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