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Calculate molality of 2.5 g of ethanoic ...

Calculate molality of 2.5 g of ethanoic acid `(CH_(3)COOH)` in 75g of benzene.

Text Solution

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`Mw_2(CH_(3)COOH) = 60 g mol^(-1)`
`m=(W_2 xx 1000)/(Mw_2 xx W_1)`
`(2.5 g xx 1000)/(60 g mol^(-1) xx 75 g)`
`0.556 mol kg^(-1)`
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