Home
Class 12
CHEMISTRY
100 mL of liquid A and 25 mL of liquid B...

`100 mL` of liquid A and `25 mL` of liquid B are mixed to form a solution of volume `125 mL`. Then the solution is

A

a.) Ideal

B

b.) Non-ideal with positive deviation

C

c.) Non-ideal with negative deviation

D

d.) Cannot be predicted

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of solution formed when 100 mL of liquid A is mixed with 25 mL of liquid B, we can follow these steps: ### Step 1: Calculate the Initial Volumes - Liquid A has a volume of 100 mL. - Liquid B has a volume of 25 mL. - Total initial volume (V_initial) = Volume of A + Volume of B = 100 mL + 25 mL = 125 mL. ### Step 2: Determine the Final Volume After Mixing - After mixing, the total volume of the solution is given as 125 mL (V_final). - Therefore, V_final = 125 mL. ### Step 3: Calculate the Change in Volume (ΔV) - ΔV (change in volume) = V_final - V_initial = 125 mL - 125 mL = 0 mL. ### Step 4: Analyze the Type of Solution - For an ideal solution, the change in volume upon mixing (ΔV) is equal to 0, and the change in enthalpy (ΔH) is also equal to 0. - Since we have found that ΔV = 0, we can conclude that the solution behaves ideally. ### Conclusion - The solution formed by mixing 100 mL of liquid A and 25 mL of liquid B is an **ideal solution**. ---
To determine the type of solution formed when 100 mL of liquid A is mixed with 25 mL of liquid B, we can follow these steps: ### Step 1: Calculate the Initial Volumes - Liquid A has a volume of 100 mL. - Liquid B has a volume of 25 mL. - Total initial volume (V_initial) = Volume of A + Volume of B = 100 mL + 25 mL = 125 mL. ### Step 2: Determine the Final Volume After Mixing ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos

  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

100 mL of liquid A and 25 mL of liquid B are mixed to formal solution of volume 125 mL. Then the solution is ideal or not .

100 ml of liquid A and 25 ml of liquid B is mixed to give a solution which does not obey Raoult's law. The volume of the solution

100 ml of liquid A and 25 ml of liquid B is mixed to give a solution which does not obey Raoult's law. The volume of the solution

The solution which boil at constant temperature like a pure liquid and possess same composition in liquid as well as vapour state are called azeotropes. The components of azetropes cannot be separated by fractional distillation. Only non-ideal solutions form azeotropes. Solutions with negative deviation form maximum boiling azeotrope and the solutions with positive deviation form minimum boiling azeotrope. The boiling point of an azeotrope is never equal to the boiling points of any of the components of the azeotrope. Answer the following question: The azeotropic solutions of two miscible liquids 100 mL of liquid A and 50 mL of liquid B are mixed to form 138 mL solution. It is

A: 10ml of liquid A mixed with 20ml of liquid B total volume of solution is 30 ml. R: A and B will ideal solution.

The density of 3M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

The density of 2M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

10 mL of a liquid A were mixed with 10 mL of liquid B. The volume of resulting solution was found to be 19.9 mL. What do you conclude?

The density of 3 M solution of NaCl is 1.25 "g mL"^(-1) . The molality of the solution is :

If 100 mL of 0.6 N H_(2)SO_(4) and 200 mL of 0.3 N HCl are mixed together, the normality of the resulting solution will be