Assuming ideal behaviour, calculate the pressure of `1.0 molal` solution of a non-volatile molecular solute in water at `50@C` . The vapour presure of water at `50@C` is `0.222 atm`.

Explanation

To calculate the pressure of a 1.0 molal solution of a non-volatile molecular solute in water at 50°C, we will use Raoult's Law, which states that the vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.

### Step-by-Step Solution:

1. **Identify Given Data:**
- Vapor pressure of pure water at 50°C, \( P^0 = 0.222 \, \text{atm} \)
- Molality of the solution, \( m = 1.0 \, \text{molal} \)

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