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At 20^@C, the vapour pressure of pure li...

At `20^@C`, the vapour pressure of pure liquid `A` is `22 mm Hg` and that of pure liquid `B` is `75 mm Hg`. What is the composition of the solution of these two components that has vapour pressure of `48.5 mm Hg` at this temperature?

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To find the composition of the solution of two components A and B that has a vapor pressure of 48.5 mm Hg at 20°C, we can use Raoult's Law. Here’s the step-by-step solution: ### Step 1: Write down the given data - Vapor pressure of pure liquid A, \( P^0_A = 22 \, \text{mm Hg} \) - Vapor pressure of pure liquid B, \( P^0_B = 75 \, \text{mm Hg} \) - Total vapor pressure of the solution, \( P_{\text{total}} = 48.5 \, \text{mm Hg} \) ### Step 2: Use Raoult's Law ...
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