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A solution containing 30 g of a non-vola...

A solution containing `30 g` of a non-volatile solute in exactly `90 g` of water has a vapour pressure of `21.85 mm` of `25^(@)C` . Further `18 g` of water is then added to the solution, the new vapour pressure becomes `22.15 mm` of `Hg` at `25 C`. Calculate the (a) molecular mass of the solute and (b) vapour pressure of water at `25^(@)C`.

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To solve the problem step by step, we will follow the given information and apply the relevant concepts of vapor pressure and mole fractions. ### Given Data: - Mass of solute (W₂) = 30 g - Mass of water (W₁) = 90 g - Initial vapor pressure of the solution (P₁) = 21.85 mm Hg - Mass of water added = 18 g - New vapor pressure of the solution (P₂) = 22.15 mm Hg ...
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