`10 g` of glucose (molar mass 180) and `20 g` of sucrose (molar mass 342) are dissolved in `100 g` of water. What will be the vapour pressure of the resultant solution if the vapour pressure of water is `30 mm Hg`?

Explanation

To solve the problem step by step, we will use Raoult's Law, which states that the vapor pressure of a solution is directly related to the mole fraction of the solvent in the solution.

### Step 1: Calculate the number of moles of glucose and sucrose.

1. **Moles of glucose**:
\[ \text{Moles of glucose} = \frac{\text{mass of glucose}}{\text{molar mass of glucose}} = \frac{10 \, \text{g}}{180 \, \text{g/mol}} = 0.0556 \, \text{mol} \]
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