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Lowering of vapour pressure due to a sol...

Lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is
a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`

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To solve the problem of lowering of vapor pressure due to a solute in a 1 molal aqueous solution at 100°C, we will follow these steps: ### Step 1: Understand the Concept The lowering of vapor pressure can be calculated using Raoult's Law, which states: \[ \Delta P = P^0 - P_s \] where \(P^0\) is the vapor pressure of the pure solvent, and \(P_s\) is the vapor pressure of the solution. ...
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