Equal amounts of a solute are dissolved in equal amounts of two solvents `A` and `B`. The lowering of vapour pressure of solution `A` has twice the lowering of vapour pressure for solution `B`. If `Mw_(A)` and `Mw_(B)` are the molecular weights of solvents `A` and `B`, respectively , then
a.`Mw_(A) = Mw_(B)` , b. `Mw_(A) = Mw_(B)//2`,
c.`Mw_(A) = 4Mw_(B)`, d. `Mw_(A) = 2Mw_(B)`

Explanation

To solve the problem, we need to analyze the relationship between the lowering of vapor pressure in two solutions containing equal amounts of a solute dissolved in equal amounts of two different solvents, A and B.

### Step-by-Step Solution:

1. **Understanding the Problem**:
- We have two solvents, A and B.
- Equal amounts of a solute are dissolved in equal amounts of both solvents.
- The lowering of vapor pressure of solution A (ΔP_A) is twice that of solution B (ΔP_B).
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