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On dissolving 3.24 g of sulphur in 40 g ...

On dissolving `3.24 g` of sulphur in `40 g` of benzene, the boiling point of the solution was higher than sulphur? (`K_(b)` for benzene = `2.53 K kg mol^(-1)` , atomic mass of sulphur `= 32 g mol^(-1)`).

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To solve the problem of determining the elevation in boiling point when dissolving 3.24 g of sulfur in 40 g of benzene, we will follow these steps: ### Step 1: Calculate the number of moles of sulfur To find the number of moles of sulfur, we use the formula: \[ \text{Moles of solute} = \frac{\text{mass of solute (g)}}{\text{molar mass of solute (g/mol)}} \] Given: ...
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