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1.4 g of acetone dissolved in 100 g of b...

`1.4 g` of acetone dissolved in `100 g` of benzene gave a solution which freezes at `277.12 K`. Pure benzene freezes at `278.4 K`.`2.8` of solid `(A)` dissolved in `100 g` of benzene gave a solution which froze at `277.76 K`. Calculate the molecular mass of `(A)`.

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To solve the problem, we will use the freezing point depression formula and the data provided in the question. ### Step-by-Step Solution: 1. **Calculate the Freezing Point Depression for Acetone:** - The freezing point of pure benzene is \( 278.4 \, K \). - The freezing point of the solution with acetone is \( 277.12 \, K \). - The change in freezing point (\( \Delta T_f \)) is calculated as: ...
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