Home
Class 12
CHEMISTRY
An aqueous solution of a non-volatile so...

An aqueous solution of a non-volatile solute boils at `100.17^(@)C`. At what temperature will the solution freeze? (Given: `K_(b) = 0.512` and `K_(f) = 1.86`)

Text Solution

AI Generated Solution

To solve the problem of finding the freezing point of an aqueous solution of a non-volatile solute that boils at 100.17°C, we can follow these steps: ### Step 1: Determine the boiling point elevation (ΔT_b) The boiling point elevation (ΔT_b) is calculated using the formula: \[ \Delta T_b = T_{b, \text{solution}} - T_{b, \text{pure solvent}} \] ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

An aqueous solution of a non-electrolyte boils at 100.52^@C . The freezing point of the solution will be

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .

An aqueous solution of a non-volatile solute freezes at 272.4 K, while pure water freezes at 273.0 K. Determine the following: (Given K_(f)= 1.86 "K kg mol"^(-1), K_(b) = 0.512 "K kg mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm of Hg) (1) The molality of solution (2) Boiling point of solution (3) The lowering of vapour pressure of water at 298 K

A dilute solution of a non-volatile solute in water freezes at — 0.2°C. At what temperature (in °C) the same solution will boil? (Kt for H_2O = 1.86°C m ^(-1) and K0 for H_2O = 0 515°C m^(-1) )

An aqueous solution boils at 101^(@)C . What is the freezing point of the same solution? (Gives : K_(f) = 1.86^(@)C// m "and" K_(b) = 0.51^(@)C//m )

The boiling point of an aqueous solution of a non-volatile solute is 100.15^(@)C . What is the freezing point of an aqueous solution obtained by dilute the above solution with an equal volume of water. The values of K_(b) and K_(f) for water are 0.512 and 1.86^(@)C mol^(-1) :

The boiling point of an aqueous solution of a non-volatile solute is 100.15^(@)C . What is the freezing point of an aqueous solution obtained by dilute the above solution with an equal volume of water. The values of K_(b) and K_(f) for water are 0.512 and 1.86^(@)C mol^(-1) :

An aqueous solution of a solute AB has b.p. of 101.08^(@)C( AB is 100% ionised at boiling point of the solution ) and freezes at -1.80 ^(@)C . Hence, AB(K_(b)//K_(f)=0.3)

The relative lowering of vapour pressure of an aqueous solution of a non-volatile solute of molecular weight 60 (which neither dissociates nor associates in the solution) is 0.018. If K_(f) of water is 1.86^(@)Cm^(-1) the depression in freezing point will be :

If the boiling point of an aqueous solution containing a non-volatile solute is 100.1^(@)C . What is its freezing point? Given latent heat of fusion and vapourization of water 80 cal g^(-1) and 540 cal g^(-1) , respectively.