Home
Class 12
CHEMISTRY
A solution of urea in water has boiling ...

A solution of urea in water has boiling point of `100.15^(@)C`. Calculate the freezing point of the same solution if `K_(f)` and `K_(b)` for water are `1.87 K kg mol^(-1)` and `0.52 K kg mol^(-1)`, respectively.

Text Solution

Verified by Experts

`DeltaT_(b) =(100.15 - 100) = 0.15^(@)C`
We know that `DeltaT_(b) = "Molality" xx K_(B)`
Molality `= (DeltaT_(b))/(K_(B)) = (0.15)/(0.50) = 0.2884`
`DeltaT_(b) = "Molality" xx K_(f)`
`= 0.2884 xx 1.87`
`= 0.54^(@)C`
Thus, the freezing point of the solution `= -0.54^(@)C`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

A solution of urea in water has a boiling point of 100*18^@C . Calculate the freezing point of the solution.(K for water is 1*86 " K kg " mol^(-1) and K_b " for water is " 0*512 " K kg " mol^(-l) ).

A solution containing 0.11kg of barium nitrate in 0.1kg of water boils at 100.46^(@)C . Calculate the degree of ionization of the salt. K_(b) (water) = 0.52 K kg mol^(-1) .

An aqueous solution of urea has a freezing point of -0.515^(@)C . Predict the osmotic pressure (in atm) of the same solution at 37^(@)C . Given: Kf (Water) = 1.86K kg per mol

A solution of urea (mol. Mass 60 g mol^(-1) ) boils of 100.18^(@)C at one one atmospheric pressure. If k_(f) and K_(b) for water are 1.86 and 0.512 K kg mol^(-1) respectively, the above solution will freeze at:

A solution of urea boils at 100.18^(@)C at the atmospheric pressure. If K_(f) and K_(b) for water are 1.86 and 0.512K kg mol^(-1) respectively, the above solution will freeze at,

For an aqueous solution freezing point is -0.186^(@)C . The boiling point of the same solution is (K_(f) = 1.86^(@)mol^(-1)kg) and (K_(b) = 0.512 mol^(-1) kg)

45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

If 0.1 m aqueous solution of calcium phosphate is 80% dissociated then the freezing point of the solution will be (K_f of water = 1.86K kg mol^(-1))

A solution containg 12 g of a non-electrolyte substance in 52 g of water gave boiling point elevation of 0.40 K . Calculate the molar mass of the substance. (K_(b) for water = 0.52 K kg mol^(-1))

What should be the freezing point of aqueous solution containing 17g of C_(2)H(5)OH is 1000g of water ( K_(f) for water = 1.86 deg kg mol^(-1) )?