Home
Class 12
CHEMISTRY
On dissolving 0.25 gof a non-volatile su...

On dissolving `0.25 g`of a non-volatile substance in`30 mL` benzene `(density 0.8 g mL^(-1))`, its freezing point decreases by `0.25^(@)C` . Calculate the molecular mass of non-volatile substance `(K_(f) = 5.1 K kg mol^(-1))`.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Calculate the mass of the solvent (benzene) We know the density of benzene and its volume. The mass can be calculated using the formula: \[ \text{Mass} = \text{Density} \times \text{Volume} \] ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

By dissolving 13.6 g of a substance in 20 g of water, the freezing point decreased by 3.7^(@)C . Calculate the molecular mass of the substance. (Molal depression constant for water = 1.863K kg mol^(-1))

The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53 K kg mol^(-1) .

The solution of 2.5 g of a non-volatile substance in 100 g of benzene boiled at a temperature 0.42^(@)C higher than the b.p. of pure benzene. Calculate mol. Wt. of the substance. ( K_(b) of benzene is 2.67 K kg "mole"^(-1) )

1.355 g of a substance dissolved in 55 g of CH_(3)COOH produced a depression in the freezing point of 0.618^(@)C . Calculate the molecular weight of the substance (K_(f)=3.85)

A solution containing 12.5g of a non electrolyte substance in 175g of water gave a boiling point elevation of 0.70 K. Calculate the molar mass of the substance. (Elevation constant for water, K_(b) = 0.52 K kg "mol"^(-1) )

A solution containing 12.5 g of non-electrolyte substance in 185 g of water shows boiling point elevation of 0.80 K. Calculate the molar mass of the substance. ( K_b=0.52 K kg mol^(-1) )

A solution containg 12 g of a non-electrolyte substance in 52 g of water gave boiling point elevation of 0.40 K . Calculate the molar mass of the substance. (K_(b) for water = 0.52 K kg mol^(-1))

The addition of 0.643 g of a compound to 50 mL of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51 to 5.03^(@)C . If K_(f) for benzene is 5.12 , calculate the molecular weight of the compound.

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .