Home
Class 12
CHEMISTRY
Ethylene glycol is used as an antifreeze...

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at `-6^(@)C.(K_(f)" for "HH_(2)O=1.85" K mol"^(-1)"kg")`

Text Solution

Verified by Experts

Given,
`DeltaT =6^(@)C`,`W_(2)=4 kg = 4000g`,`Mw_(2)=62`,`K_(f)=1.85`
`W_(2) =(Mw_(2)xxW_(1)xxDeltaT)/(1000xxK_(f))`
`(62xx4000xx6)/(1000xx1.85) =804.32 g`.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at -6^@C . (K_f " for " H_2O = 1*85 K "mole"^(-1) kg)

In a cold climate water gets frozen causing damage to radiator of a car. Ethylene glycol is used as an anifreezing agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at -6^(@) . ( K_(f) for water = 1.85 kg mol^(-1) )

How many grams of methyl alcohol should be added to 10 litre tank of water to prevent its freezing at 268K ? (K_(f) for water is 1.86 K kg mol^(-1))

Water is used in car radiators. In winter season, ethylene glycol is added to water so that water may not freeze. Assuming ethylene glycol to be non-volatile, calculate minimum amount of ethylene glycol that must be added to 6.0 kg of water to prevent it from freezing at -0.3^(@)C . The molal depression constant of water is 1.86^(@) .

Calculate the amount of KCl which must be added to 1kg of water so that the freezing point is depressed by 2K . ( K_(f) for water =1.86K kg "mol"^(-1) ).

Calcualate the amount of NaCl which must be added to 100 g water so that the freezing point, depressed by 2 K . For water K_(f) = 1.86 K kg mol^(-1) .

The weight of ethyl alcohol which must be added to 1.0 L of water so that the solution will freeze at 14^@F is (K_f of water = 1.86 K kg mol^(-1) )

Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water = 1.86 K mol^(-1) kg )

Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water = 1.86 K mol^(-1) kg )

The amount of ice that will separate out from a solution containing 25 g of ethylene glycol in 100 g of water that is cooled to -10^(@)C , will be [Given : K_(f) "for" H_(2)O = 1.86K mol^(-1) kg ]