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The molal freezing point depression cons...

The molal freezing point depression constant of benzene`(C_(6)H_(6))` is `4.90 K kg mol^(-1)`. Selenium exists as a polymer of the type `Se_(x)`. When `3.26 g` of selenium is dissolved in `226 g` of benzene, the observed freezing point is `0.112^(@)C` lower than pure benzene. Deduce the molecular formula of selenium. (Atomic mass of `Se=78.8 g mol^(-1)`)

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To deduce the molecular formula of selenium (Se) from the given data, we will follow these steps: ### Step 1: Understand the given data - The molal freezing point depression constant (Kf) of benzene = 4.90 K kg mol⁻¹ - Mass of selenium (solute) = 3.26 g - Mass of benzene (solvent) = 226 g - Depression in freezing point (ΔTf) = 0.112 °C - Atomic mass of selenium (Se) = 78.8 g mol⁻¹ ...
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