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The freezing point of 0.08 molal NaHSO(4...

The freezing point of `0.08 molal NaHSO_(4)` is `-0.345^(@)C`. Calculate the percentage of `HSO_(4)+O` ions that transfers a proton to water. Assume `100%` ionization of `NaHSO_(4)` and `K_(t)` for `H_(2)O = 1.86 K molality^(-1)`.

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To solve the problem, we need to follow these steps: ### Step 1: Understand the dissociation of NaHSO₄ When NaHSO₄ dissociates in water, it produces Na⁺ and HSO₄⁻ ions. The HSO₄⁻ ion can further dissociate into H⁺ and SO₄²⁻ ions. The dissociation can be represented as: \[ \text{NaHSO}_4 \rightarrow \text{Na}^+ + \text{HSO}_4^- \] \[ \text{HSO}_4^- \rightleftharpoons \text{H}^+ + \text{SO}_4^{2-} \] ...
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