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200cm^(3) of an aqueous solution of a pr...

`200cm^(3)` of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300K is found to be `2.57xx10^(-3)` bar. Calculate the molar mass of the protein.

Text Solution

Verified by Experts

The given values are
`pi=2.57xx10^(-3)` bar
`V=200 cm^(3)=0.2 L`
`T=300 K`
`R=0.083 L` bar `mol^(-1) K^(-1)`
Using the formula,
`Mw_("solute")=(W_("solute")xxRxxT)/(pixxV)`
`= (1.26 g xx 0.083 L` "bar" `"mol"^(-1) K^(-1)xx300 K)/(2.57xx10^(-3) "bar"xx0.2 L)`
`= 61022 g mol^(-1)`
Thus, the molecular weight of solute is `61022 g mol^(-1)`.
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