Home
Class 12
CHEMISTRY
The osmotic pressure of a solution was f...

The osmotic pressure of a solution was found to be `8 atm` when `8 mol ` of a non-volatile solute was dissolved in `V` L of solution at `300 K`.Calculate the volume of solution `(R=0.0821 L-"atm" K^(-1) "mol"^(-1))`

Text Solution

AI Generated Solution

To solve the problem of calculating the volume of the solution based on the given osmotic pressure, we can use the formula for osmotic pressure: \[ \pi = C \cdot R \cdot T \] Where: - \(\pi\) = osmotic pressure (in atm) ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

The osmotic pressure of 8% solution of urea at 300 K is

The osmotic pressure of a solution containing 5 g of substance (molar mass =100) in 308 m L of solution was found to be 4.0 atm at 300 K . Calculate the value of solution constant (R)

The osmotic pressure of a solution containing 0.1 mol of solute per litre at 300 K is

The osmotic pressure of a solution containing 0.3 mol of solute per litre at 300 K is

The osmotic pressure of a solution containing 0.2 mol of solute per litre at 300 K is

The osmotic pressure of a solution containing 0.6 mol of solute per litre at 300 K is

The osmotic pressure of a solution containing 0.1 mol of solute per litre at 273 K is

The osmotic pressure of a solution containing 0.1 mol of solute per litre at 323 K is

The osmotic pressure of a solution containing 0.4 mol of solute per litre at 273 K is

The osmotic pressure of a solution containing 0.4 mol of solute per litre at 323 K is