A solution of non-volite solute in water freezes at `-0.30^(@)C`.The vapour pressure of pure water at `298 K` is `23.51 mm Hg`.and `K_(f)` for water is `1.86 `degree per molal. Calculate the vapour pressure of this solution at `298 K`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the depression in freezing point (ΔTf)
The depression in freezing point is given by the formula:
\[ \Delta T_f = T_0 - T_f \]
Where:
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