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0.1 M aqueous solution of MgCl(2) at 300...

`0.1 M` aqueous solution of `MgCl_(2)` at `300 K` is `4.92 atm`. What will be the percentage ionination of the salt?
a.`49%` , b. `59%` ,c.`79%` d. `69%`

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To solve the problem of determining the percentage ionization of the salt \( MgCl_2 \) in a \( 0.1 M \) aqueous solution at \( 300 K \) with an osmotic pressure of \( 4.92 atm \), we can follow these steps: ### Step 1: Use the formula for osmotic pressure The formula for osmotic pressure (\( \pi \)) is given by: \[ \pi = iCRT \] Where: ...
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