Home
Class 12
CHEMISTRY
The freezing point of an aqueous solutio...

The freezing point of an aqueous solution of `KCN` containing `0.1892 mol Kg^(-1)`, the freezing point of the solution was found to be `-0.530^(@)C`. If the complex formation takes place according to the following equation:
`Hg(CN)_(2)`, the freezing point of the solution was found to be `-0.530^(@)C`. If the complex formation takes place according to the following equation:
`Hg(CN)_2 +nKCN hArr K_n[Hg (CN)_(n+2)]`
what is the formula of the complex? [`K_(f)(H_(2)O)` is `1.86 K kg mol^(-1)`]

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understanding the Freezing Point Depression The freezing point depression (\( \Delta T_f \)) can be calculated using the formula: \[ \Delta T_f = K_f \cdot i \cdot m \] where: ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos

  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

Freezing point of solution is marked as

The lowest freezing point of 0.1 M aqueous solution is of:

The freezing point of 1% aqueous solution of calcuim nitrate will be

At freezing point of a solution there is always

Which of the following solutions has the maximum freezing point?

Which of the following solutions has the minimum freezing point

The freezing point of 0.05 m solution of glucose in water is (K1 = 1.86°C m^(-1) )

0.1 M aqueous solution of K_4[Fe(CN)_6] will have the same freezing point as 0.1 M aqueous solution of

The freezing poing of an aqueous solution of a non-electrolyte is -0.14^(@)C . The molality of this solution is [K_(f) (H_(2)O) = 1.86 kg mol^(-1)] :

The freezing point of an aqueous solution of KCN containing 0.1892" mole"//"kg" H_(2)O was -0.704^(@)C . On adding 0.095 mole of Hg(CN)_(2) , the freezing point of solution was -0.53^(@)C . Assuming that complex is formed according to the reaction Hg(CN)_(2)+xCN^(-) to Hg(CN)_(x+2)^(x-) and also Hg(CN)_(2) is limiting reagent, find x.