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To 250 mL of water, x g of acetic acid i...

To `250 mL` of water, `x g` of acetic acid is added. If `11.5%` of acetic acid is dissociated, the depressin in freezing point comes out `0.416`. What will be the value of `x` if `K_(f) ("water")=1.86 K kgmol^(-1)` and density of water is `0.997 g mL`.

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To solve the problem, we will follow these steps: ### Step 1: Calculate the mass of the solvent (water) Given: - Volume of water = 250 mL - Density of water = 0.997 g/mL Using the formula: ...
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