Home
Class 12
CHEMISTRY
The freezing point of a solution contani...

The freezing point of a solution contaning `0.3 g` of acetic acid in `43 g` of benzene reduces by `0.3^(@)`. Calculate the Van's Hoff factor
"(`K_(f)` for benzene =`5.12 K kg mol^(-1)`)"

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understand the formula for freezing point depression The freezing point depression (\( \Delta T_f \)) is given by the formula: \[ \Delta T_f = i \cdot K_f \cdot m \] where: ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

The freezing point of a solution containing 0*3 gms of acetic acid in 30 gms of benzene is lowered by 0*45 K . Calculate the van't Hoff factor. (At. wt. of C = 12, H = 1, 0 = 16, K_f " for benzene " = 5.12 " K kg mole"^(-1) ).

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

The freezing point of a solution containing of 0.2g of acetic acid in 20.0g of benzene is lowered 0.45^(@)C . Calculate. (i) the molar mass of acetic acid from this data (ii) Van't Hoff factor [For benzene, K_(f)=5.12K kg "mol"^(-1) ] What conclusion can you draw from the value of Van't Hoff factor obtained ?

The freezing point of a solution containing 5.85 g of NaCl in 100 8 of water is -3.348^(@)C . Calculate van't Hoff factor for this solution. What will be the experimental molecular weight of NaCl? ( K_(f) for water = 1.86 K kg mol^(-1) , at. wt. Na = 23, Cl = 35.5)

Acetic acid associates in benzene to form a dimer. 1.65 g of acetic acid when dissolved in 100 g of benzene raised the boiling point by 0.36^(@)C . Calculate the Van't Hoff factor and degree of association of acetic acid. ( K_(b) for benzene= 2.57^(@)C )

The freezing point of a solution containing 0.1g of K_3[Fe(CN)_6] (Mol. Wt. 329) in 100 g of water ( K_f =1.86K kg mol^(−1) ) is:

The elevation in boiling point when 0.30 g of acetic acid is dissolved in 100 g of benzene is 0.0633^(@)C . Calculate the molecular weight of acetic acid from this data. What conclusion can you draw about the molecular state of the solute in the solution? (Given K_(b) for benzene =2.53"K kg mol"^(-1) , at wt. of C=12, H=1, O=16)

(a) State Raoult's law for a solution containing volatile components. How does Raoult' s law become a special case of Henry's law? (b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (K_(f)" for benzene "=5.12 kg mol^(-1))