Properties such as boiling point, freezing point, and vapour pressure of a pure solvent change when solute molecules are added to get homogenous solution. These are called colligative properties.
Anwer the following questions:
i. `NaNO_(3)` ii.`BaCl_(2)`
iii. `K_(3)[Fe(CN)_(6)]` iv. `C_(6)H_(12)O_(6)`
Increasing order of Van't Hoff factor

Options

A. `(iv) lt (ii) lt (i) lt (iii)`
B. `(iv) lt (i) lt (ii) lt (iii)`
C. `(iv) lt (iii) lt (ii) lt (i)`
D. `(iv) lt (i) lt (ii) lt (iii)`

Explanation

To determine the increasing order of the Van't Hoff factor (i) for the given compounds, we need to analyze how each compound dissociates in solution.

1. **NaNO₃ (Sodium Nitrate)**:
- Sodium nitrate dissociates into two ions in solution: Na⁺ and NO₃⁻.
- Therefore, the Van't Hoff factor (i) for NaNO₃ is 2.

2. **BaCl₂ (Barium Chloride)**:
- Barium chloride dissociates into three ions in solution: Ba²⁺ and 2 Cl⁻.
- Therefore, the Van't Hoff factor (i) for BaCl₂ is 3.

3. **K₃[Fe(CN)₆] (Potassium Hexacyanoferrate(II))**:
- This compound dissociates into four ions in solution: 3 K⁺ and 1 [Fe(CN)₆]³⁻.
- Therefore, the Van't Hoff factor (i) for K₃[Fe(CN)₆] is 4.

4. **C₆H₁₂O₆ (Glucose)**:
- Glucose is a non-electrolyte and does not dissociate into ions in solution.
- Therefore, the Van't Hoff factor (i) for C₆H₁₂O₆ is 1.

Now, we can summarize the Van't Hoff factors for each compound:
- NaNO₃: i = 2
- BaCl₂: i = 3
- K₃[Fe(CN)₆]: i = 4
- C₆H₁₂O₆: i = 1

**Increasing order of Van't Hoff factor**:
1. C₆H₁₂O₆ (i = 1)
2. NaNO₃ (i = 2)
3. BaCl₂ (i = 3)
4. K₃[Fe(CN)₆] (i = 4)

Thus, the final increasing order of the Van't Hoff factor is:
C₆H₁₂O₆ < NaNO₃ < BaCl₂ < K₃[Fe(CN)₆]