At `25^(@)C` , the free energy of formation of `H_(2)O(l)` is `-56,700 Cal mol^(-1)`. The free energy of ionization of water to `H^(o+)` and `overset(c-)(O)H` is `19050 cal mol^(-1)`. What is the reversible `EMF` of the following cell at `25^(@)C:`
`H_(2)(g)(1 atm)|H^(o+)||overset(c-)(O)H,O_(2)(g),1atm`

Explanation

To solve the problem, we need to find the reversible EMF of the cell reaction given the Gibbs free energies of formation and ionization of water.

### Step-by-Step Solution:

1. **Identify the Reactions:**
- The first reaction is the formation of water:
\[
\text{H}_2(g) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{H}_2O(l)
...