Calculate the potential corresponding to the following cell. Given
`Pt|Co^(2+)(2.0M),Co^(3+)(0.01M)||Cr^(3+)(0.5M),Cr_(2)O_(7)^(2-)(4.0M),H^(o+)(1.5M))|Pt `
`E^(-)._(Co^(2+)|Co^(3+))=-1.82V`
`E^(-)._(Cr_(2)O_(7)^(2-)|Cr^(3+))=+1.33V`

Explanation

To calculate the potential of the given electrochemical cell, we will follow these steps:

### Step 1: Identify the Anode and Cathode
In the cell notation given:
- Left side (Pt | Co²⁺(2.0M), Co³⁺(0.01M)) is the **anode**.
- Right side (Cr³⁺(0.5M), Cr₂O₇²⁻(4.0M) | H⁺(1.5M)) is the **cathode**.

### Step 2: Write the Half-Reactions
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