Knowing that `K_(sp)` for `AgCl` is `1.0 xx 10^(-10)`, calculate `E` for a silver `//` silver chloride electrode immersed in `1.00 M KCl ` at `25^(@)C.E^(c-)._(Ag^(o+)|Ag)=0.799V`.

Explanation

To calculate the electrode potential (E) for a silver/silver chloride electrode immersed in 1.00 M KCl at 25°C, we can follow these steps:

### Step 1: Understand the solubility product (Ksp)
The solubility product \( K_{sp} \) for \( AgCl \) is given as \( 1.0 \times 10^{-10} \). This represents the equilibrium between solid \( AgCl \) and its ions in solution:

\[ AgCl (s) \rightleftharpoons Ag^+ (aq) + Cl^- (aq) \]
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